1919 Oldenburg state election
German state election
The 1919 Oldenburg state election was held on 23 February 1919 to elect the 48 members of the constituent assembly of the Free State of Oldenburg.[1] The election was held in Birkenfeld on 9 March.[1]
Results
| Party | Votes | % | Seats | |
|---|---|---|---|---|
| Social Democratic Party of Germany | 65,027 | 33.44 | 16 | |
| German Democratic Party | 60,442 | 31.08 | 15 | |
| Centre Party | 42,716 | 21.97 | 11 | |
| German People's Party | 22,128 | 11.38 | 5 | |
| German National People's Party | 4,140 | 2.13 | 1 | |
| Total | 194,453 | 100.00 | 48 | |
| Valid votes | 194,453 | 99.74 | ||
| Invalid/blank votes | 511 | 0.26 | ||
| Total votes | 194,964 | 100.00 | ||
| Registered voters/turnout | 292,956 | 66.55 | ||
| Source: Elections in the Weimar Republic,[1] Elections in Germany[2] | ||||
References
- ^ a b c Gonschior, Andreas. "Der Freistaat Oldenburg Wahl zur Landesversammlung 1919". Wahlen in der Weimarer Republik. Archived from the original on 2001-05-27. Retrieved 20 May 2021.
- ^ Schröder, Valentin. "Landtagswahlen Oldenburg". Wahlen in der Deutschland. Archived from the original on 2005-02-24. Retrieved 19 May 2021.
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- See also: Elections and referendums in Germany
- Elections in the Free State of Prussia
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