1988 WTA German Open – Doubles

Claudia Kohde-Kilsch and Helena Suková were the defending champions but lost in the final 6–2, 4–6, 6–4 against Isabelle Demongeot and Nathalie Tauziat.

Seeds

Champion seeds are indicated in bold text while text in italics indicates the round in which those seeds were eliminated. The top four seeded teams received byes into the second round.

Draw

Key

Final

Top half

Bottom half

	First round							Second round							Quarterfinals							Semifinals
	7	K Horvath  D Van Rensburg	6	6
		B Fulco  E Raponi-Longo	2	4				7	K Horvath  D Van Rensburg	6	4	6
		B Bowes  J Smoller	2	3					J Halard  P Paradis	3	6	2
		J Halard  P Paradis	6	6											7	K Horvath  D Van Rensburg	6	2	6
		S Cecchini S Goleš	0	6	6										3	J Novotná  M Paz	3	6	3
		C Bakkum  B Schultz	6	1	2				S Cecchini S Goleš	6	4
								3	J Novotná  M Paz	7	6
																						7	K Horvath  D Van Rensburg	4	3
	5	I Demongeot  N Tauziat	6	4	6																	5	I Demongeot  N Tauziat	6	6
		N Dias  P Tarabini	0	6	3			5	I Demongeot  N Tauziat	6	6
		L Ferrando  L Garrone	6	6	6				L Ferrando  L Garrone	0	3
		M Torres  C Wood	7	2	4										5	I Demongeot  N Tauziat	4	6	7
		G Miró  G Mosca	6	6												G Miró  G Mosca	6	1	6
		S Norris  R Seeman	1	4					G Miró  G Mosca	2	6	7
								2	H Mandlíková  E Pfaff	6	2	6

References

• 1988 WTA German Open Doubles Draw